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Jake Arrieta has longest World Series no-hit bid in 47 years

Cubs starter didn’t allow a hit until the 6th inning of Game 2

World Series - Chicago Cubs v Cleveland Indians - Two Photo by Jason Miller/Getty Images

Staked to a big lead, Jake Arrieta took a no-hitter into the sixth inning in Game 2 of the World Series against the Cleveland Indians on Wednesday night at Progressive Field in Cleveland, the deepest no-hit try in 47 years.

Indians second baseman Jason Kipnis doubled to right-center field with one out in the sixth inning, the first hit allowed on the night by Arrieta. Kipnis came around to score, the only run allowed by Arrieta in his 5⅔ innings, to go with six strikeouts.

Arrieta left the game with a 5-1 lead.

As mentioned on the Fox broadcast, Arrieta’s no-hit bid was the longest in a World Series game since Jerry Koosman got through six innings before allowing a hit in Game 2 of the 1969 Fall Classic.

Koosman, pitching for the Mets, allowed a single to Paul Blair leading off the seventh inning 47 years ago, one of two hits allowed by Koosman in a 2-1 victory for New York, in a series the Mets would win in five games.

Arrieta ran into some trouble early with back-to-back two-out walks in the first inning on Wednesday night. But unlike Game 1, Cleveland wasn’t able to translate those into runs, and from there it was smooth sailing for the reigning NL Cy Young Award winner.

After the first-inning walks, Arrieta retired 14 of his next 15 batters faced until Kipnis doubled in the sixth inning.

Arrieta has a 3.78 ERA in three postseason starts in 2016, with 16 strikeouts and four walks. He has two career no-hitters, one each in 2015 and 2016.